2x^2-189x-95=0

Solution for 2x^2-189x-95=0 equation:

2x^2-189x-95=0

a = 2; b = -189; c = -95;
Δ = b2-4ac
Δ = -1892-4·2·(-95)
Δ = 36481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36481}=191$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-189)-191}{2*2}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-189)+191}{2*2}=\frac{380}{4}
=95
$